MCQ
If $x\left[\begin{array}{l}1 \\ 2\end{array}\right]+y\left[\begin{array}{l}2 \\ 5\end{array}\right]=\left[\begin{array}{l}4 \\ 9\end{array}\right],$ then
  • A
    $x=1, y=2$
  • $x=2, y=1$
  • C
    $x=1, y=-1$
  • D
    $x=3, y=2$

Answer

Correct option: B.
$x=2, y=1$
We have, $x\left[\begin{array}{l}1 \\ 2\end{array}\right]+y\left[\begin{array}{l}2 \\ 5\end{array}\right]=\left[\begin{array}{l}4 \\ 9\end{array}\right]$
$\Rightarrow\left[\begin{array}{c} x+2 y \\ 2 x+5 y \end{array}\right]$
$=\left[\begin{array}{l} 4 \\ 9 \end{array}\right]$
$\Rightarrow x+2 y=4  ...(i)$
and $2 x+5 y=9 ........(ii)$
Solving $(i)$ and $(ii),$ we get $x=2, y=1$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

A vector parallel to the line of intersection of the plance $\vec{\text{r}}.(3\hat{\text{i}}-\hat{\text{j}}+\hat{\text{k}})=1$ and $\vec{\text{r}}.(\hat{\text{i}}-4\hat{\text{j}}+2\hat{\text{k}})=2$ is:
The feasible solution of an $\text{LP}$ problem, is $ .........$
The maximum value of $f(x) = {x \over {4 + x + {x^2}}}$ on $[ - 1,\,1]$ is
Find the area of bounded by $\text{y}=\sin\text{x}$ from $\text{x}=\frac{\pi}{4}$ to $\text{x}=\frac{\pi}{2}:$
Directions: In the following questions, the Assertions $(A)$ and Reason$(s)\ (R)$ have been put forward. Read both the statements carefully and choose the correct alternative from the following:
Assertion $(A) \frac{\text{d}}{\text{dx}}(\text{x}^2+\text{x}+1)^4=(\text{x}^2+\text{x}+1)^3(2\text{x}+1)$
Reason $(R) (\text{fog}'=\text{f'}[\text{g(x)}].\text{g'(x)}$
If a spherical balloon has a variable diameter $3x + \frac{9}{2}$ , then the rate of change of its volume with respect to $x$
The area bounded by the curve $y = 4x - x^2$ and the $x-$ axis is:
$f (x) =$ $\int\limits_0^x {\,t\,(t\, - \,1)\,\,(t\, - \,2)\,dt} $ takes on its minimum value when:
A wire of length $36\, \mathrm{~m}$ is cut into two pieces, one of the pieces is bent to form a square and the other is bent to form a circle. If the sum of the areas of the two figures is minimum, and the circumference of the circle is $\mathrm{k}$ $(meter),$ then $\left(\frac{4}{\pi}+1\right) \mathrm{k}$ is equal to ..... .
Let $\text{A}=\begin{bmatrix} 2 & 3 \\ 5 & -2 \end{bmatrix}$ be such that $A^{-1} = kA,$ then k equals: