MCQ
If $x\left[\begin{array}{l}1 \\ 2\end{array}\right]+y\left[\begin{array}{l}2 \\ 5\end{array}\right]=\left[\begin{array}{l}4 \\ 9\end{array}\right]$, then
  • A
    $x=1, y=2$
  • B
    $x=2, y=1$
  • C
    $x=1, y=-1$
  • D
    $x=3, y=2$

Answer

We have, $x\left[\begin{array}{l}1 \\ 2\end{array}\right]+y\left[\begin{array}{l}2 \\ 5\end{array}\right]=\left[\begin{array}{l}4 \\ 9\end{array}\right]$
\[\Rightarrow\left[\begin{array}{c}
x+2 y \\
2 x+5 y
\end{array}\right]=\left[\begin{array}{l}
4 \\
9
\end{array}\right]
\]$\Rightarrow x+2 y=4$  ...(i) and $2 x+5 y=9$   ....(ii)
Solving (i) and (ii), we get $x=2, y=1$

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