MCQ
If $x+y=-4$, then $x^3+y^3-12 x y+64=$
- A-64
- B128
- C0
- Dnone of these
✓
Answer
C. 0
$\begin{array}{l}\text { We have, } x+y=-4 \text { or, } x+y+4=0 . \\ \therefore \quad x^2+y^3+4^3=3 x y \times 4 \text { or, } x^3+y^3+64=12 x y \text { or, } x^3+y^3-12 x y+64=0\end{array}$
$\begin{array}{l}\text { We have, } x+y=-4 \text { or, } x+y+4=0 . \\ \therefore \quad x^2+y^3+4^3=3 x y \times 4 \text { or, } x^3+y^3+64=12 x y \text { or, } x^3+y^3-12 x y+64=0\end{array}$
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