Rajasthan BoardEnglish MediumSTD 12 ScienceMATHSDifferentiation5 Marks
Question
If $xy = e^{x-y},$ find $\frac{\text{dy}}{\text{dx}}$
✓
Answer
The given function is $xy = e^{x-y}$
Taking logarithm on both the sides, we obtain
$\log(\text{xy})=\log\big(\text{e}^{\text{x}-\text{y}})$
$\Rightarrow\log\text{x}+\log\text{y}=(\text{x}-\text{y})\log\text{e}$
$\Rightarrow\log\text{x}=\log\text{y}=(\text{x}-\text{y})\times1$
$\Rightarrow\log\text{x}=\log\text{y}=\text{x}-\text{y}$
Differentiating both sides with respect to $x, $ we obtain
$\frac{\text{d}}{\text{dx}}(\log\text{x})+\frac{\text{d}}{\text{dx}}(\log\text{y})=\frac{\text{d}}{\text{dx}}(\text{x})-\frac{\text{dy}}{\text{dx}}$
$\Rightarrow\frac{1}{\text{x}}+\frac{1}{\text{y}}\frac{\text{dy}}{\text{dx}}=1-\frac{\text{dy}}{\text{dx}}$
$\Rightarrow\big(1+\frac{1}{\text{y}}\big)\frac{\text{dy}}{\text{dx}}=1-\frac{1}{\text{x}}$
$\Rightarrow\big(\frac{\text{y}+1}{\text{y}}\big)\frac{\text{dy}}{\text{dx}}=\frac{\text{x}-1}{\text{x}}$
$\therefore\frac{\text{dy}}{\text{dx}}=\frac{\text{y}(\text{x}-1)}{\text{x}(\text{y}+1)}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.