MCQ
If $x^y=y^{ x }$, then $\frac{d y}{d x}=$
- A$\frac{x(x \log y-y)}{y(y \log x-x)}$
- ✓$\frac{y(y \log x-x)}{x(x \log y-y)}$
- C$\frac{y^2(1-\log x)}{x^2(1-\log y)}$
- D$\frac{y(1-\log x)}{x(1-\log y)}$
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