If y =1 3 x^2-2 x-1 , then d y d x = ? - Vidyadip

MCQ

If $y =\frac{1}{\sqrt{3 x^2-2 x-1}}$, then $\frac{ d y}{ d x}=$ ?

A
$\frac{-2}{3}(3 x-2)\left(3 x^2-2 x-1\right)^{\frac{-3}{2}}$
B
$\frac{-3}{2}(3 x-2)\left(3 x^2-2 x-1\right)^{\frac{-3}{2}}$
C
$(3 x-1)\left(3 x^2-2 x-1\right)^{\frac{-3}{2}}$
✓
$-(3 x-1)\left(3 x^2-2 x-1\right)^{\frac{-3}{2}}$

✓

Answer

Correct option: D.

$-(3 x-1)\left(3 x^2-2 x-1\right)^{\frac{-3}{2}}$

$-(3 x-1)\left(3 x^2-2 x-1\right)^{\frac{-3}{2}}$

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