MCQ
If $y = c{e^{{{\sin }^{ - 1}}x}}$, then corresponding to this the differential equation is
  • $\frac{{dy}}{{dx}} = \frac{y}{{\sqrt {1 - {x^2}} }}$
  • B
    $\frac{{dy}}{{dx}} = \frac{1}{{\sqrt {1 - {x^2}} }}$
  • C
    $\frac{{dy}}{{dx}} = \frac{x}{{\sqrt {1 - {x^2}} }}$
  • D
    None of these

Answer

Correct option: A.
$\frac{{dy}}{{dx}} = \frac{y}{{\sqrt {1 - {x^2}} }}$
a
(a) $y = c{e^{{{\sin }^{ - 1}}x}}$. Differentiate it w.r.t. $x$, we get

$\frac{{dy}}{{dx}} = c{e^{{{\sin }^{ - 1}}x}}.\frac{1}{{\sqrt {1 - {x^2}} }} = \frac{y}{{\sqrt {1 - {x^2}} }}$ or $\frac{{dy}}{{dx}} = \frac{y}{{\sqrt {1 - {x^2}} }}$.

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