MCQ
If $y = c{e^{{{\sin }^{ - 1}}x}}$, then corresponding to this the differential equation is
- ✓$\frac{{dy}}{{dx}} = \frac{y}{{\sqrt {1 - {x^2}} }}$
- B$\frac{{dy}}{{dx}} = \frac{1}{{\sqrt {1 - {x^2}} }}$
- C$\frac{{dy}}{{dx}} = \frac{x}{{\sqrt {1 - {x^2}} }}$
- DNone of these