MCQ
If $y = {e^{(1 + {{\log }_e}x)}}$, then the value of ${{dy} \over {dx}} = $
- ✓$e$
- B$1$
- C$0$
- D${\log _e}x\,\,{e^{{{\log }_e}ex}}$
$\Rightarrow \frac{{dy}}{{dx}} = e$.
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