MCQ
If $y = {e^{\sqrt x }}$, then ${{dy} \over {dx}}$ equals
- ✓${{{e^{\sqrt x }}} \over {2\sqrt x }}$
- B${{\sqrt x } \over {{e^{\sqrt x }}}}$
- C${x \over {{e^{\sqrt x }}}}$
- D${{2\sqrt x } \over {{e^{\sqrt x }}}}$
==> $\frac{{dy}}{{dx}} = {e^{\sqrt x }}.\frac{d}{{dx}}\sqrt x $
==> $\frac{{dy}}{{dx}} = \frac{{{e^{\sqrt x }}}}{{2\sqrt x }}$.
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Let $a \in S$ and $A =\left[\begin{array}{ccc}1 & 0 & a \\ -1 & 1 & 0 \\ - a & 0 & 1\end{array}\right]$
If $\sum_{ a \in S } \operatorname{det}(\operatorname{adj} A )=100 \lambda$, then $\lambda$ is equal to
($A$) $g^{\prime}(2)=\frac{1}{15}$ ($B$) $h^{\prime}(1)=666$ ($C$) $h(0)=16$ ($D$) $h(g(3))=36$