MCQ
If $y = f(x) = \frac{{ax + b}}{{cx - a}}$, then $x$ is equal to
- A$1/f(x)$
- B$1/f(y)$
- C$yf(x)$
- ✓$f(y)$
$⇒ x(cy - a) = b + ay$
$⇒ x = \frac{{ay + b}}{{cy - a}} = f(y)$.
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Statement $-I$ : ${A^{ - 1}} = \frac{1}{7}\left( {5I - A} \right).$
Statement $II$ : the polynomial $A^3 - 2A^2 - 3A + I$ can be reduced to $5\, (A - 4I)$.