MCQ
If $y = f(x) = \frac{{x + 2}}{{x - 1}}$, then $x = $
- ✓$f(y)$
- B$2f(y)$
- C$\frac{1}{{f(y)}}$
- DNone of these
$\Rightarrow \,\,x = \frac{3}{{y - 1}} + 1 = \frac{{y + 2}}{{y - 1}} = f(y)$.
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Statement $1:$ The quadratic equation has at least one root in the interval $(0, 1).$
Statement $2:$ The Rolle's theorem is applicable to function $g(x)$ on the interval $[0, 1 ].$
$z^5=1$ then value of $\left| {\begin{array}{*{20}{c}}
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