MCQ
If $y = f(x) = \frac{{x + 2}}{{x - 1}}$, then $x = $
- ✓$f(y)$
- B$2f(y)$
- C$\frac{1}{{f(y)}}$
- DNone of these
$\Rightarrow \,\,x = \frac{3}{{y - 1}} + 1 = \frac{{y + 2}}{{y - 1}} = f(y)$.
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