MCQ
If $y = f(x) = \frac{{x + 2}}{{x - 1}}$, then $x = $
  • $f(y)$
  • B
    $2f(y)$
  • C
    $\frac{1}{{f(y)}}$
  • D
    None of these

Answer

Correct option: A.
$f(y)$
a
(a) $y = \frac{{x + 2}}{{x - 1}}\,\,$

$\Rightarrow \,\,x = \frac{3}{{y - 1}} + 1 = \frac{{y + 2}}{{y - 1}} = f(y)$.

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