MCQ
If $y =\left(5 x ^3-4 x ^2-8 x \right)^9$, then $\frac{d y}{d x}=$
- ✓$9\left(5 x^3-4 x^2-8 x\right)^8\left(15 x^2-8 x-8\right)$
- B$9\left(5 x^3-4 x^2-8 x\right)^9\left(15 x^2-8 x-8\right)$
- C$9\left(5 x^3-4 x^2-8 x\right)^8\left(5 x^2-8 x-8\right)$
- D$9\left(5 x^3-4 x^2-8 x\right)^9\left(5 x^2-8 x-8\right)$