MCQ
If $y = {\log _{\sin x}}(\tan x),$ then ${\left( {{{dy} \over {dx}}} \right)_{\pi /4}} = $
- A${4 \over {\log 2}}$
- B$ - 4\log 2$
- ✓${{ - 4} \over {\log 2}}$
- DNone of these
==> $\frac{{dy}}{{dx}} = \frac{{(\log \sin x)\left( {\frac{{{{\sec }^2}x}}{{\tan x}}} \right) - (\log \tan x)(\cot x)}}{{{{(\log \sin x)}^2}}}$
==> ${\left( {\frac{{dy}}{{dx}}} \right)_{\pi /4}} = \frac{{ - 4}}{{\log 2}}$ (On simplification).
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