Question
If y = $\frac{\sin^{-1}\text{x}}{\sqrt{\text{1 - x}^{2}}}$ show that
$(1-\text{x}^{2})\frac{\text{d}^{2}\text{y}}{\text{dx}}-\text{3x}\frac{\text{dy}}{\text{dx}}-\text{y}=0.$

Answer

$\sqrt{\text{1 - x}^{2}}\text{ y}=\sin^{-1}\text{x}$
$\sqrt{\text{1 - x}^{2}}\text{ }\frac{\text{dy}}{\text{dx}}-\frac{\text{xy}}{\sqrt{\text{1 - x}^{2}}}=\frac{1}{\sqrt{\text{1 - x}^{2}}}$
$\Rightarrow\text{(1 - x)}^{2}\text{ }\frac{\text{dy}}{\text{dx}}-\text{xy}=1$
$\Rightarrow\text{(1 - x)}^{2}\text{ }\frac{\text{d}^{2}\text{y}}{\text{dx}^{2}}-\text{ 2x }\frac{\text{dy}}{\text{dx}}-\text{ x }\frac{\text{dy}}{\text{dx}}-\text{y}=0$
$\Rightarrow\text{(1 - x)}^{2}\text{ }\frac{\text{d}^{2}\text{y}}{\text{dx}^{2}}-\text{ 3x }\frac{\text{dy}}{\text{dx}}-\text{ y }=0.$

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