MCQ
If $y = \sqrt {\sin x + y} ,$ then ${{dy} \over {dx}}$ equals to
  • A
    ${{\sin x} \over {2y - 1}}$
  • ${{\cos x} \over {2y - 1}}$
  • C
    ${{\sin x} \over {2y + 1}}$
  • D
    ${{\cos x} \over {2y + 1}}$

Answer

Correct option: B.
${{\cos x} \over {2y - 1}}$
b
(b) $y = \sqrt {\sin x + y} ,$ ==> ${y^2} = \sin x + y$

Differentiate with respect to $ x$ , 

$2y.\frac{{dy}}{{dx}} = \cos x + \frac{{dy}}{{dx}}$

==> $\frac{{dy}}{{dx}}(2y - 1) = \cos x$

==> $\frac{{dy}}{{dx}} = \frac{{\cos x}}{{2y - 1}}$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free