MCQ
If $y =\sqrt{x+\sqrt{x+\sqrt{x+\ldots+\text { to }} \infty \infty}}$ then $\frac{d y}{d x}=$
- A$\frac{1}{2 y+1}$
- ✓$\frac{1}{2 y-1}$
- C$\frac{x}{y+1}$
- D$\sqrt{\frac{x}{y+1}}$
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$\left\{\left| a + b \omega+ c \omega^2\right|^2: a , b , c \text { distinct non-zero integers }\right\}$ equals. . . . .