MCQ
If $y =\sqrt{x+\sqrt{x+\sqrt{x+\ldots+\text { to }} \infty \infty}}$ then $\frac{d y}{d x}=$
- A$\frac{1}{2 y+1}$
- B$\frac{1}{2 y-1}$
- C$\frac{x}{y+1}$
- D$\sqrt{\frac{x}{y+1}}$
✓
Answer
(b) $\frac{1}{2 y-1}$
Explanation: $y =\sqrt{(x+y)}$
$\begin{array}{l}y^2=x+y \\
2 yy^{\prime}=1+y^{\prime}\end{array}$
Explanation: $y =\sqrt{(x+y)}$
$\begin{array}{l}y^2=x+y \\
2 yy^{\prime}=1+y^{\prime}\end{array}$
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