If $y_1 = 5 (mm)\ \sin\pi t$ is equation of oscillation of source $S_1$ and $y_2$ $=$ $5$ $(mm)$ $sin(\pi t + \pi /6)$ be that of $S_2$ and it takes $1$ $sec$ and $\frac{1}{2}\ sec$ for the transverse waves to reach point $A$ from sources $S_1$ and $S_2$ respectively then the resulting amplitude at point $A$, is .... $mm$
  • A$5\sqrt {2 + \sqrt 3 } $
  • B$5\sqrt 3 /2 $
  • C$5$
  • D$5\sqrt 2 $
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