If y=1+x+x^2 2! +x^3 3! + .. , then d y d x = _________ . - Vidyadip

MCQ

If $y=1+x+\frac{x^2}{2!}+\frac{x^3}{3!}+\ldots .$. , then $\frac{d y}{d x}=$ _________ .

✓
$y$
B
$y-1$
C
$0$
D
Does not exist

✓

Answer

Correct option: A.

$y$

A

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