MCQ
If $y=e^{\frac{1}{2} \log \left(1+\tan ^2 x\right)}$, then $\frac{d y}{d x}$ is equal to
  • A
    $\frac{1}{2} \sec ^2 x$
  • B
    $\sec ^2 x$
  • $\sec x \tan x$
  • D
    $e^{\frac{1}{2} \log \left(1+\tan ^2 x\right)}$

Answer

Correct option: C.
$\sec x \tan x$
$y=e^{\frac{1}{2} \log \left(1+\tan ^2 x\right)}=\left(\sec ^2 x\right)^{1 / 2}=\sec x$
$\therefore \frac{d y}{d x}=\sec x \tan x$

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