Answer

Correct option: B.
$\frac{-4 x}{1-x^4}$
(b) : $y=\log \left(\frac{1-x^2}{1+x^2}\right)$
$
\Rightarrow y=\log \left(1-x^2\right)-\log \left(1+x^2\right)
$
Differentiating w.r.t. $x$, we get
$
\frac{d y}{d x}=\frac{1}{1-x^2}(-2 x)-\frac{1}{1+x^2}(2 x)=\frac{-4 x}{1-x^4}
$

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