Question
If $\text{y}=\sin^{-1}\text{x}+\cos^{-1}\text{x},$ find $\frac{\text{dy}}{\text{dx}}.$

Answer

We have, $\text{y}=\sin^{-1}\text{x}+\cos^{-1}\text{x}$
$\Rightarrow\text{y}=\frac{\pi}{2}$
$\Big[\because\sin^{-1}\text{x}+\cos^{-1}\text{x}=\frac{\pi}{2}\Big]$
$\Rightarrow\frac{\text{dy}}{\text{dx}}=0$

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