Question
If $\text{y}=\text{x}\sin\text{y},$ prove that $\frac{\text{dx}}{\text{dx}}=\frac{\sin^2\text{y}}{(1-\text{x}\cos\text{y})}$
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$\frac{\text{dr}}{\text{dt}}=-\text{rt, r}(0)=\text{r}_{0}$