MCQ
If z = 2 - 3i then z2 - 4z + 13 =
  • A
    0
  • B
    1
  • C
    2
  • D
    3

Answer

  1. 0

Solutions:

z = 2 - 3i

z2 = 22 - 32 - 12i

= -5 - 12i

$\therefore$ z2 - 4z + 13

= (-5 - 12i) - 4(2 - 3i) + 13

= -5 - 12i - 8 + 12i + 13

= -13 + 13

= 0

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