MCQ
If z = 2 - 3i then z2 - 4z + 13 =
- A0
- B1
- C2
- D3
Solutions:
z = 2 - 3i
z2 = 22 - 32 - 12i
= -5 - 12i
$\therefore$ z2 - 4z + 13
= (-5 - 12i) - 4(2 - 3i) + 13
= -5 - 12i - 8 + 12i + 13
= -13 + 13
= 0
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The two successive terms in the expansion of (1 + x)24 whose coefficients are in the ratio 1 : 4 are:
$[\text{Hint}:\frac{^{24}\text{C}_\text{r}}{^{24}\text{C}_{\text{r}+1}}=\frac{1}{4}\ \frac{\text{r}+1}{24-\text{r}}\ \frac{1}{4}\Rightarrow4\text{r}+4=24-4\Rightarrow\text{r}=4]$
The number of parallelograms that can be formed from a set of four parallel lines intersecting another set of three parallel lines is.