MCQ
If $z = \frac{{7 - i}}{{3 - 4i}}$ then ${z^{14}} = $
- A${2^7}$
- B${2^7}i$
- C${2^{14}}i$
- ✓$ - {2^7}i$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(x + 2)^{n-1} + (x + 2)^{n-2}. (x + 1) + (x + 2)^{n-3} . (x + 1)^2; + ...... + (x + 1)^{n-1}$ is :
$\frac{3}{{1! + 2! + 3!}} + \frac{4}{{2! + 3! + 4!}} + \frac{5}{{3! + 4! + 5!}} + ...... + \frac{{2008}}{{\left( {2006} \right)! + \left( {2007} \right)! + \left( {2008} \right)!}}$ is equal to