MCQ
If $z$ is a complex number, then $\left(\overline{z^{-1}}\right)(\bar{z})=$
  • 1
  • B
    -1
  • C
    $0$
  • D
    i

Answer

Correct option: A.
1
(A)
Let $z =x+ i y$. Then, $\overline{ z }=x- i y$ and $z ^{-1}=\frac{1}{x+ i y}$
$\Rightarrow\left(\overline{ z ^{-1}}\right)=\frac{1}{x- i y} \Rightarrow\left(\overline{ z ^{-1}}\right)=\frac{x+ i y}{x^2+y^2}$
$\therefore \quad\left(\overline{ z ^{-1}}\right) \overline{ z }=\frac{x+ i y}{x^2+y^2}(x- i y)=1$

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