Question
If $z_1, z_2$ are two complex numbers such that $|\text{z}_1|=|\text{z}_2|$ and $\text{arg(z}_1)+\text{arg(z}_2)=\pi,$ then show that $\text{z}_1=-\bar{\text{z}}_2.$
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$\text{A}'\cup\text{B}=\text{U}\Rightarrow\text{A}\subset\text{B.}$