MCQ
If ${z_1},{z_2} \in C$, then $amp\,\left( {\frac{{{{\rm{z}}_{\rm{1}}}}}{{{{{\rm{\bar z}}}_{\rm{2}}}}}} \right) = $
- A$amp\,({z_1}{\overline z _2})$
- B$amp\,({\overline z _1}{z_2})$
- ✓$amp\,\left( {\frac{{{z_2}}}{{{{\bar z}_1}}}} \right)$
- D$amp\,\left( {\frac{{{z_1}}}{{{z_2}}}} \right)$