MCQ
Impossible orbital among the following is :
- ✓$3f$
- B$2p$
- C$4d$
- D$2s$
✓
Answer
Correct option: A.
$3f$
If the value of principle quantum number is $3$.
So the maximum possible value of Azimuthal quantum number is $(3 - 1) = 2$ which describes the $d$ subshell.
But for $f$ subshell, the value of $l$ must be $3$.
So, $3f$ orbital is not possible at all.
So the maximum possible value of Azimuthal quantum number is $(3 - 1) = 2$ which describes the $d$ subshell.
But for $f$ subshell, the value of $l$ must be $3$.
So, $3f$ orbital is not possible at all.
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