MCQ
In a chemical equilibrium $A + B$ $\rightleftharpoons$ $C + D$, when one mole each of the two reactants are mixed, $0.6 $ mole each of the products are formed. The equilibrium constant calculated is
- A$1$
- B$0.36$
- ✓$2.25$
- D$4/9$
✓
Answer
Correct option: C.
$2.25$
(c) $A+ B$ $ \rightleftharpoons $ $C+ D$
Initial $1$ $1$ $0$ $0$
remaining at equilibrium $0.4$ $0.4$ $0.6$ $0.6$
$K = \frac{{[C]\,\,[D]}}{{[A]\,\,[B]}} = \frac{{0.6 \times 0.6}}{{0.4 \times 0.4}} = \frac{{36}}{{16}} = 2.25$.
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