In a class, 40% of the students study math and science. 60% of the students study math. What is the probability of a student studying science given he/she is already studying math?
A
0.43
B
0.40
C
0.67
D
0.60
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C
0.67
P(M and S) = 0.40
P(M) = 0.60
$\text{P(S|M})=\frac{\text{P (M and S)}}{\text{P(S)}}=\frac{0.40}{0.60}=\frac23=0.67$
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