MCQ
In a common emitter transistor circuit, the base current is $40 \,\mu A$, then $V_{B E}$ is .......... $V$
  • A
    $2$
  • $0.2$
  • C
    $0.8$
  • D
    $0$

Answer

Correct option: B.
$0.2$
b
(b)

Applying kirchoff

$10-245 \times 40 \times 10^{-3}=V_{B E}$

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