Question
In a compound microscope, maximum magnification is obtained when the final image
✓
Answer
(b) is formed at the least distance of distinct vision
Explanation: Magnification of compound microscope is given by
$m =\left(\frac{v_o}{u_o}\right)\left(1+\frac{D}{t_o}\right)$ when final image is formed at near point
Whereas, $m =\left(\frac{ v _o}{ u _o}\right)\left(\frac{D}{f_e}\right)$, when final image is formed at infinity.
Hence, magnification is maximum when final image is formed at near point (least distance of distinct vision).
Explanation: Magnification of compound microscope is given by
$m =\left(\frac{v_o}{u_o}\right)\left(1+\frac{D}{t_o}\right)$ when final image is formed at near point
Whereas, $m =\left(\frac{ v _o}{ u _o}\right)\left(\frac{D}{f_e}\right)$, when final image is formed at infinity.
Hence, magnification is maximum when final image is formed at near point (least distance of distinct vision).
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
A metal rod moves at a constant velocity in a direction perpendicular to its length. A constant uniform magnetic field exists in space in a direction perpendicular to the rod as well as its velocity. Select the correct statement(s) from the following (a) The entire rod is at the same electric potential(b) There is an electric field in the rod(c) The electric potential is highest at the centre of the rod and decreases towards its ends(d) The electric potential is lowest at the centre of the rod and increases towards its ends
Electric charge is measured in:
A wavefront presents one, two and three HPZ at points A, B and C respectively. If the ratio of consecutive amplitudes of HPZ is 4 : 3, then the ratio of resultant intensities at these point will be (a) 169 : 16 : 256(b) 256 : 16 : 169(c) 256 : 16 : 196(d) 256 : 196 : 16
In the circuit shown in figure, the current drawn from the battery is $4A.$ If $10\Omega$ resistor is replaced by $20\Omega$ resistor, then current drawn from the circuit will be
→A group of $N$ cells whose emf varies directly with the internal resistance as per the equation $E_N = 1.5 r_N$ are connected as shown in the figure below. The current $I$ in the circuit is
→Assertion : To protect any instrument from external magnetic field, it is put inside an iron body.
Reason : Iron is a magnetic substance.(a) If both assertion and reason are true and the reason is the correct explanation of the assertion.(b) If both assertion and reason are true but reason is not the correct explanation of the assertion.(c) If assertion is true but reason is false.(d) If the assertion and reason both are false.
Reason : Iron is a magnetic substance.(a) If both assertion and reason are true and the reason is the correct explanation of the assertion.(b) If both assertion and reason are true but reason is not the correct explanation of the assertion.(c) If assertion is true but reason is false.(d) If the assertion and reason both are false.
A thin lens is made with a material having refractive index $\mu=1.5.$ Both the sides are convex. It is dipped in water $(\mu=1.33).$ It will behave like:
→The magnetic field at the centre of a current carrying loop is B and its area is A. Magnetic moment of the loop will be :
In the ground state in ...A... electrons are in stable equilibrium while in ...B... electrons always experiences a net force. Here, A and B refer to?
Near and far points of a human eye are(a) 0 and 25 cm(b) 0 and ¥(c) 25 cm and 100 cm(d) 25 cm and ¥