MCQ
In a frequency distribution, the mid-value of a class is 15 and the class intervals is 4. The lower limit of the class is:
- A14
- B12
- C13
- D10
✓
Answer
- 13
Solution:
Let the lower limit be x.
Class interval = 4
Upper limit = x + 4
Now, mid - value of a class $=\frac{\text{x}+4+\text{x}}{2}=\text{x}+2=15(\text{given)}$
x = 13 = lower limit
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