Question
In a meter bridge, two unknown resistances R and S, when connected between the two gaps, give a null point is 60 cm from one end. What is the ratio of R and S?

Answer

Here, $I_R=60 cm$
$
\therefore I _{ S }=(100-60) cm =40 cm
$
$
\therefore \frac{ R }{ S }=\frac{l_{ R }}{l_{ S }}=\frac{60}{40}=\frac{3}{2}
$

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