In a mixture of A and B components shows negative deviation when

MCQ

In a mixture of $A$ and $B$ components shows negative deviation when

A
$A-B$ interaction is weaker than $A-A$ and $B-B$ interaction
✓
$A-B$ interaction is stronger than $A-A$ and $B-B$ interaction
C
$\Delta {V_{\operatorname{mi} x}}\, > \,0,\,\Delta {S_{\operatorname{mi} x}}\, > \,0$
D
$\Delta {V_{\operatorname{mi} x}}\, = \,0,\,\Delta {S_{\operatorname{mi} x}}\, =\,0$

✓

Answer

Correct option: B.

$A-B$ interaction is stronger than $A-A$ and $B-B$ interaction

b
In a mixture component $A$ and component $B$ Shows negative Deviation as, $\Delta V _{\text {mixing }}\,<\,0$

i.e. For Negative Deviation, $\Delta V _{\text {mixing }}= O , \Delta H _{\text {mixing }}=-$ ve

Because, the forces of attraction between components $A$ and $B$ is greater.

Due to that the tendency of escaping of molecules $A B$ from solution becomes less than that of pure liquids.

$A - B$ attractive forces is greater than $A - A$ and $B - B$ attractive forces.

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