In a multiple- choice test consisting of 8 questions, each questi… - Vidyadip

Question

In a multiple- choice test consisting of $8$ questions, each question has four options. For each of the questions, exactly one of the four options is the right answer.$A$ student answers all the questions by choosing one option for each question. The number of ways in which the student can get exactly $5$ correct answers is

✓

Answer

d
(d)

Each question can be answered in 4 different ways

Required number of ways

$={ }^8 C _5 \times(1) \times(3)^3$

$=1512$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

If the sum of the first $20$ terms of the series

$\log _{\left(7^{\frac{1}{2}}\right)} x+\log _{\left(7^{\frac{1}{3}}\right)} x+\log _{\left(7^{\frac{1}{4}}\right)} x+\ldots$ is $460,$ then $x$ is equal to

If $a^2 + b^2 + c^2$ = $1$, then maximum passible value of $3a + 4b + 12c$ is equal to (where $a,b,c\ \in R$)-

If $\beta=\lim _{x \rightarrow 0} \frac{e^{x^3}-\left(1-x^3\right)^{\frac{1}{3}}+\left(\left(1-x^2\right)^{\frac{1}{2}}-1\right) \sin x}{x \sin ^2 x}$

then the value of $6 \beta$ is $\qquad$

Let $A^{-1}=\left[\begin{array}{lll}1 & 2017 & 2 \\ 1 & 2017 & 4 \\ 1 & 2018 & 8\end{array}\right]$ Then, $|2 A|-\left|2 A^{-1}\right|$ is equal to

Let ${T_n}$ denote the number of triangles which can be formed using the vertices of a regular polygon of $n$ sides. If ${T_{n + 1}} - {T_n} = 21,$ then $n$ equals

If ${x_1} = 3$ and $x > 0$ then $\mathop {\lim }\limits_{n \to \infty } {x_n}$ is equal to

The total number of permutations of the letters of the word $“BANANA”$ is

Let $f : N \rightarrow R$ be a function such that $f(x+y)=2 f(x) f(y)$ for natural numbers $x$ and $y$. If $f(1)=2$, then the value of $\alpha$ for which

$\sum \limits_{k=1}^{10} f(\alpha+k)=\frac{512}{3}\left(2^{20}-1\right)$ holds, is

If $f(x)\, = \frac{x}{{1 + |x|}}$ for $x \in R,$ then $f'(0) = $

If three successive terms of a$G.P.$ with common ratio $r(r>1)$ are the lengths of the sides of a triangle and $[\mathrm{r}]$ denotes the greatest integer less than or equal to $r$, then $3[r]+[-r]$ is equal to :