MCQ
In a parallel plate capacitor, the capacity increases if:
  • A
    Area of the plate is decreased.
  • B
    Distance between the plates is increases.
  • C
    Area of the plate is increased.
  • D
    Dielectric constant decreases.

Answer

  1. Area of the plate is increased.

Explanation:

Hint:- Check the dependence of capacitance on certain quantities.

In a parallel plate capacitor, the capacitance is $\text{C}=\frac{\text{k}\in_0\text{A}}{\text{d}};$

Where, k is the dielectric constant, $\in_0$​ is the permittivity constant, A is the area of the conduction and d is the distance between plates.

From here we can see C is directly proportional to k, $\in_0$​,A and inversely proportional to d.

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