In a parallel plate capacitor the separation between the plates is $3\,mm$ with air between them. Now a $1\,mm$ thick layer of a material of dielectric constant $2$ is introduced between the plates due to which the capacity increases. In order to bring its capacity to the original value the separation between the plates must be made......$mm$
Medium
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(c) $K = \frac{t}{{t - d'}}$ $==>$ $2 = \frac{1}{{1 - d'}}$ ==> $d' = \frac{1}{2}\,mm$
So new distance $ = 3 + \frac{1}{2} = 3.5\,mm$
So new distance $ = 3 + \frac{1}{2} = 3.5\,mm$
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