MCQ
In a parallelogram $ABCD$, angle $A$ and angle $B$ are in the ratio $1 : 2$. Find the angle $A$.
- ✓$60^\circ$
- B$90^\circ$
- C$30^\circ$
- D$45^\circ$
As we know, the sum of adjacent angles of a parallelogram is equal to $180^\circ $ and opposite angles are equal to each other.
Thus, in parallelogram $ABCD$ angle $A$ and angle $B$ are adjacent to each other
Let angle $A = x$ and angle $B = 2x.$
So, $x + 2x = 180^\circ $
$3x = 180^\circ $
$x = 60^\circ $
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