MCQ
In a parallelogram ABCD, if $\angle A=75^{\circ}$, then $\angle D-\angle C=$
  • A
    $5^{\circ}$
  • B
    $20^{\circ}$
  • $30^{\circ}$
  • D
    $60^{\circ}$

Answer

Correct option: C.
$30^{\circ}$
(c) $30^{\circ}$
We have, $\angle A=75^{\circ}$
$\therefore \quad \angle C=75^{\circ} \text { and } \angle D=105^{\circ} \Rightarrow \angle D-\angle C=30^{\circ}$

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