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Quadrilaterals — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsQuadrilaterals1 Mark
MCQ
In a parallelogram ABCD, if $\angle\text{DAB}=75^\circ$ and $\angle\text{DBC}=60^\circ,$ then $\angle\text{BDC}=$
  • A
    75°
  • B
    60°
  • C
    45°
  • D
    55°
✓

Answer

  1. 45°
    Solution:

    In parallelogram ABCD,
    $\angle\text{A}+\angle\text{D}=180^\circ$
    $\Rightarrow\angle\text{D}=180^\circ-75^\circ=105^\circ$
    $\angle\text{ADB}=\angle\text{DBC}$ (Alternate angles)
    $\Rightarrow\angle\text{ADB}=60^\circ$
    $\angle\text{BDC}=\angle\text{ADC}-\angle\text{ADB}=105^\circ-60^\circ=45^\circ$

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