MCQ
In a parallelogram $\angle{\text{A}}:\angle{\text{B}}=1:2$ Then, $\angle\text{A}=$
- A$30^\circ$
- ✓$60^\circ$
- C$45^\circ$
- D$90^\circ$
$\angle{\text{A}}+\angle{\text{B}}=180^\circ$
$\angle{\text{A}}:\angle{\text{B}}=1:2$
Stun of the ratios $= 1 + 2 = 3$
$\therefore\angle\text{A}=\frac{1}{3}\times180^\circ=60^\circ$
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