MCQ
In a polar molecule, the ionic charge is $4.8 \times {10^{ - 10}}$ $e.s.u.$ If the inter ionic distance is one $\mathop A\limits^o $ unit, then the dipole moment is ........ $\mathrm{debye}$
- A$41.8$
- B$4.18$
- ✓$4.8$
- D$0.48$
ionic distance $ = 1\,\mathop A\limits^o = {10^{ - 8}}\,cm$
we know that dipole moment = ionic charge $×$ ionic distance
$ = 4.8 \times {10^{ - 10}} \times {10^{ - 8}}$
$ = 4.8 \times {10^{ - 8}}$ e.s.u. per cm $ = 4.8$ debye.
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