In a process on a system, the initial pressure and volume are equal to the final pressure and volume. 1. The initial temperature must be equal to the final temperature. 2. The initial internal energy must be equal to the final internal energy. 3. The net heat given to the system in the process must be zero. 4. The net work done by the system in the process must be zero.

1. The initial temperature must be equal to the final temperature. 2. The initial internal energy must be equal to the final internal energy. Explanation: 1. Let initial pressure, volume and temperature be P1, V1 and T1 and final pressure, volume and temperature be P2, V2 and T2. Then, P_1V_1 T_1 = P_2V_2 T_2 _1=T_2 [P_1=P_2 and V_1=V_2 ] 2. Internal energy is given by =nC_V Since =0, =0, 3. This may not be true because the system may be isothermal and in between, heat may have been given to the system. Also, the system may have done mechanical expansion work and returned back to its original state. 4. Not necessary because an isothermal system may have done work absorbing heat from outside and coming back to the same state losing heat.

In a process on a system, the initial pressure and volume are equ…

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Question

In a process on a system, the initial pressure and volume are equal to the final pressure and volume.

The initial temperature must be equal to the final temperature.
The initial internal energy must be equal to the final internal energy.
The net heat given to the system in the process must be zero.
The net work done by the system in the process must be zero.

✓

Answer

The initial temperature must be equal to the final temperature.
The initial internal energy must be equal to the final internal energy.

Explanation:

Let initial pressure, volume and temperature be P₁, V₁ and T₁ and final pressure, volume and temperature be P₂, V₂ and T₂. Then,

$\frac{\text{P}_1\text{V}_1}{\text{T}_1}=\frac{\text{P}_2\text{V}_2}{\text{T}_2}$

$\Rightarrow\text{T}_1=\text{T}_2\ \big[\text{P}_1=\text{P}_2\ \text{and}\ \text{V}_1=\text{V}_2\big]$

Internal energy is given by $\Delta\text{U}=\text{nC}_\text{V}\Delta\text{T}$

Since $\Delta\text{T}=0,\Delta\text{U}=0,$

This may not be true because the system may be isothermal and in between, heat may have been given to the system. Also, the system may have done mechanical expansion work and returned back to its original state.
Not necessary because an isothermal system may have done work absorbing heat from outside and coming back to the same state losing heat.

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