- A$10$
- B$12$
- C$15$
- ✓$16$
$\mathrm{t}=0 \quad \mathrm{~A}_0 \quad \mathrm{~A}_0$
$t=\tau \quad A_1 \quad A_2$
$\frac{\mathrm{A}_1}{\mathrm{~A}_2}=\frac{\mathrm{A}_0(0.5)^{t /\left(L_{r i}\right)_2}}{\mathrm{~A}_0(0.5)^{t /\left(t_{\mu z}\right)_2}}=\frac{(0.5)^3}{(0.5)^7}=2^4=16$
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$ I= \frac{1}{{\sqrt 2 }} sin \left( {100\pi t} \right)$
$E=\frac{1}{\sqrt{2}} \sin (100 \pi t+\pi / 3)$
The average power in watts consumed in the circuit is
$(A)$ the process during the path $\mathrm{A} \rightarrow \mathrm{B}$ is isothermal
$(B)$ heat flows out of the gas during the path $\mathrm{B} \rightarrow \mathrm{C} \rightarrow \mathrm{D}$
$(C)$ work done during the path $\mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{C}$ is zero
$(D)$ positive work is done by the gas in the cycle $ABCDA$