MCQ
In a regular $15$ -sided polygon with all its diagonals drawn, a diagonal is chosen at random. The probability that it is neither a shortest diagonal nor a longest diagonal is
  • $\frac{2}{3}$
  • B
    $\frac{5}{6}$
  • C
    $\frac{8}{9}$
  • D
    $\frac{8}{9}$

Answer

Correct option: A.
$\frac{2}{3}$
a
(a)

Total number of diagonals of $15$ sided polygons

$={ }^{15} C_2-15=\frac{15 \times 14}{2}-15=90$

$\therefore$ Number of total shortest digonals $=15$

And number of longest digonals $=15$

$\therefore$ 'he probability that the selected diagonal is neither shortest nor longest

$=\frac{90-30}{90}=\frac{60}{90}=\frac{2}{3}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The roots of the equation $i{x^2} - 4x - 4i = 0$ are
The number of solutions of the equation $\log _{(x+1)}\left(2 x^{2}+7 x+5\right)+\log _{(2 x+5)}(x+1)^{2}-4=0, x\,>\,0$, is $....$
For $n \in N$, if $\cot ^{-1} 3+\cot ^{-1} 4+\cot ^{-1} 5+\cot ^1 n=\frac{\pi}{4}$, then $\mathrm{n}$ is equal to .........
Let $f:(0,1) \rightarrow R$ be the function defined as $f(x)=[4 x]\left(x-\frac{1}{4}\right)^2\left(x-\frac{1}{2}\right)$, where $[x]$ denotes the greatest integer less than or equal to $x$. Then which of the following statements is(are) true?

($A$) The function $f$ is discontinuous exactly at one point in $(0,1)$

($B$) There is exactly one point in $(0,1)$ at which the function $f$ is continuous but $NOT$ differentiable

($C$) The function $\mathrm{f}$ is $NOT$ differentiable at more than three points in $(0,1)$

($D$) The minimum value of the function $f$ is $-\frac{1}{512}$

${d \over {dx}}\left\{ {{{\cos }^{ - 1}}\left( {{{1 - {x^2}} \over {1 + {x^2}}}} \right)} \right\} = $
Number of points on the ellipse $\frac{{{x^2}}}{{50}} + \frac{{{y^2}}}{{20}} = 1$ from which pair of perpendicular tangents are drawn to the ellips $\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{{9}} = 1$
If $y = {({x^x})^x}$, then ${{dy} \over {dx}} =$
From $6$ different novels and $3$ different dictionaries, $4$ novels and $1$ dictionary are to be selected and arranged in a row on a shelf so that the dictionary is always in the middle. The number of such arrangements is :
The centre of the circle, which cuts orthogonally each of the three circles ${x^2} + {y^2} + 2x + 17y + 4 = 0,$ ${x^2} + {y^2} + 7x + 6y + 11 = 0,$ ${x^2} + {y^2} - x + 22y + 3 = 0$ is
If $I = \int\limits_0^{\frac{\pi }{2}} {\cos \left( {\sin x} \right)} \,dx,J = \int\limits_0^{\frac{\pi }{2}} {\sin \left( {\cos x} \right)} \,dx$ and $K = \int\limits_0^{\frac{\pi }{2}} {\cos x} \,dx$ , then