In a regular hexagon ABCDEF , AE = - Vidyadip

MCQ

In a regular hexagon $ABCDEF$ , $\overrightarrow {AE} = $

A
$\overrightarrow {AC} \,\, + \,\,\overrightarrow {AF} \,\, + \,\overrightarrow {AB} $
✓
$\overrightarrow {AC} \,\, + \,\,\overrightarrow {AF} \,\, - \,\overrightarrow {AB} $
C
$\overrightarrow {AC} \,\, + \,\,\overrightarrow {AB} \,\, - \,\,\overrightarrow {AF} $
D
None of these

✓

Answer

Correct option: B.

$\overrightarrow {AC} \,\, + \,\,\overrightarrow {AF} \,\, - \,\overrightarrow {AB} $

b
(b) Obviously, $\overrightarrow {AE} = \overrightarrow {AC} + \overrightarrow {CD} + \overrightarrow {DE} $

$ = \overrightarrow {AC} + \overrightarrow {AF} - \overrightarrow {AB} $, .$\left\{ {\,\because \,\,\overrightarrow {CD} = \overrightarrow {AF} \,{\text{and}}\,\overrightarrow {DE} = - \overrightarrow {AB} } \right\}$

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