Question
In a right angled tringle ABC, write the value of $\sin^2\text{A}+\sin^2\text{B}+\sin^2\text{C}.$

Answer

Suppose in $\text{ABC}\angle\text{B}=90^\circ$ $\Rightarrow\text{A+C}=\frac{\pi}{2}$ $\Rightarrow\text{A}=\frac{\pi}{2}-\text{C}$ $\Rightarrow\sin\text{A}=\sin\Big(\frac{\pi}{2}-\text{C}\Big)$ Now, $\sin^2\text{A}+\sin^2\text{B}+\sin^2\text{C}$ $=\sin^2\text{A}+1+\cos^2\text{A}$ $\big[\because\sin\frac{\pi}{2}=1\big]$ $=1+1=2$

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